Question

Решить уравнение; √3-x-x'2=x

Answer 1

$left { {3-x-x^2=x^2} atop {3-x-x^2 geq 0 }} right.$
$left { {{2x^2+x-3=0} atop {x^2+x-3 geq 0}} right.$
$left { {{(x-1)(x+3/2)} atop {x^2+x-3 geq 0}} right$
x=1