Question

(x-2)(x2+2x+1)=4(x+1)

Answer 1

$(x-2)(x^2+2x+1)=4(x+1)\(x-2)(x+1)^2-4(x+1)=0\(x+1)((x-2)(x+1)-4)=0\(x+1)(x^2-x-2-4)=0\(x+1)(x^2-x-6)=0\(x+1)(x+2)(x-3)=0\x_1=-1\x_2=-2\x_2=3$