Question

х3 - 6х2 + 16 = 0. Решите!!!срочно!!!

Answer 1

$x^3 - 6x^2 + 16 = 0 <=> (x - 2)(x^2 - 4x -8) = 0<=>(x-2)(x-2-2sqrt{3})(x-2+2sqrt{3})=0$
Ответ: {2; 2 + 2 sqrt(3); 2 - 2sqrt(3)}