Предмет: Алгебра, автор: Аноним

Постройте график функции а)7 х в квадрате+х-6 б)16х в квадрате-14х+3

Ответы

Автор ответа: LLWell
0

а) Функция квадратичная, значит график - парабола. Т.к. перед х^2 нет минуса - ветви параболы направлены вверх. 

Посчитаем нули функции - в них парабола будет пересекать ось х. 

7х^2+х-6=0

D=b^2-4*a*c=1+4*7*6=169

х=(-b+-sqrtD)/2a= -1; 6/7 - это наши нули. Теперь строим график. 

Лучше взять масштаб побольше, две или три клетки. 

Для того, чтобы достроить параболу до конца, рассчитаем координаты вершины параболы по формуле: 

х(верш)= -b/2а = -1/14

Для нахождения у(верш) подставляем х(верш) в функцию вместо х. 

Далее находим еще две точки и строим график. 

 

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