Question

a^3-8+6a^2-12a_________________!

Answer 1

$a^{3}-8+6a^{2}-12a=(a^{3}-2^{3})+6a(a-2)=$

$=(a-2)(a^{2}+2a+4)+6a(a-2)=(a-2)(a^{2}+2a+4+6a)=$

$=(a-2)(a^{2}+10a+4)$