Question

упростить выражение. и найти значение при x=0.04 и y=0.09
(x^2+y^2 / xy^1/2+x^3/2 - x+y / x^1/2+y^/2) * xy.

Answer 1

1)$(x^2+y^2)/x( y^{1/2} + x^{1/2}) -(x+y)/( x^{1/2}+y ^{1/2})=(x^2+y^2-x^2-xy)/$$x(x ^{1/2} +y ^{1/2})=y( ^{1/2} - x^{1/2} )(y ^{1/2}+ x^{1/2})x( x^{1/2}+y ^{1/2} )=$$y( y^{1/2} - x^{1/2} )/x$
2)$y( y^{1/2} - x^{1/2})/x *xy=y^2*( y^{1/2} - x^{1/2})$
0,09²*(0,3-0,2)=0,0081*0,1=0,00081