Question

$frac{2}{8 ^{log ^{2} _{ sqrt{3 } } } }$

Answer 1

$frac{2}{8^{log_2sqrt3}}=frac{2}{2^{3log_2{sqrt3}}}=frac{2}{2^{log_2(sqrt3)^3}}}=frac{2}{(sqrt3)^3}=frac{2}{3sqrt3}=frac{2sqrt3}{9}$