Question

решите уравнение $3^{2x+1}-9^{x}=18$

Answer 1

$3^{2x+1}-9^{x}=18 \ 3^{2x+1}-3^{2x}=18 \ 3^{2x}*(3-1)=18 \ 3^{2x} *2=18 \ 3^{2x} =9 \ 3^{2x}=3^{2} \ 2x=2 \ x=2/2=1$

Answer 2

$3* 3^{2x} -3 ^{2x} =18$
$2*3 ^{2x} =18$
$3 ^{2x} =9$
$9 ^{x} =9$⇒x=1