Предмет: Физика, автор: олеся1980

Из неподвижной лодки, масса которой 80 килограмм, прыгает на берег мальчик. Масса мальчика 40 килограмм, скорость его при прыжке 2м/с. какую скорость преобрела лодка?Решите пжл)))

Ответы

Автор ответа: воылр
0

Задача на закон сохранения импульса: 0=m*v+M*u (Эту формулу надо переобразовать) u=-(m*v)/M. 

Дано:                                   Решение:

m=40;                             u=-(40*2)/80=-1(м/c)            

v=2;

M=80;  

Найти: 

  u -? 

ответ:-1(м/с) 

                                      

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