Question

ПОМОГИТЕЕ ПЛИИЗ!!!!!!!

Answer 1

$lg(x-1)-lgx=lg, 0,6;; ; ODZ:; ; left { {{x-1>0} atop {x>0}} right. ; to ; x>1\\lg, 0,6=lgfrac{6}{10}=lgfrac{3}{5}\\lgfrac{x-1}{x}=lgfrac{3}{5}\\frac{x-1}{x}=frac{3}{5}\\5(x-1)=3x\\2x=5\\x=2,5>1$