Question

(X^6-3)*(x^3+8)<=0 помогите решить,срочно

Answer 1

$(x^6-3)(x^3+8) leq 0$

$x^6-3 leq 0\x^6 leq 3\x leq pm sqrt[6]{3}$$approx1,2$

$x^3+8 leq 0\x^3=-8\x=-2$

Ответ: $x in (-infty;-2]$U$(- sqrt[6]{3};+sqrt[6]{3} )$