Question

Решите уравнение: 12xв квадрате-(4-3)(3x+1)=-2

Answer 1

12x²-(4x-3)(3x+1)=-2
12x²-(12x²-9x+4x-3)=-2
12x²-12x²+9x-4x+3=-2
5x=-2-3
5x=-5
x=-1

Answer 2

12x²-(4x-3)(3x+1)=-2
12x²-(12x²+4x-9x-3)=-2
12x²-12x²-4x+9x+3+2=0
5x+5=0
5x=-5
x=-5/5
x=-1