Question

Рещите поэалуйста
cos(3x+pi/6)=-√3/2

Answer 1

$cos(3x+pi /6)=-sqrt{3}/2\3x+pi /6=б5pi/6+2pi n, nin Z\3x=б5pi/6-pi/6+2pi n, nin Z\x=б5pi/18-pi/18+2pi n/3, nin Z\\x_1=4pi/18+2pi n/3, nin Z\x_2=-pi/3+2pi n/3, nin Z$