Question

arccos(-√3/2)+arcsin(-√3/2)

Answer 1

$arccos(-frac{sqrt3}{2})+arcsin(-frac{sqrt3}{2})=pi -arccosfrac{sqrt3}{2}-arcsinfrac{sqrt3}{2}=\\=pi -frac{pi }{6}-frac{pi}{3}=frac{6pi -pi -2pi }{6}=frac{3pi }{6}=frac{pi }{2}$

Вообще есть формула  $arcsin alpha +arccos alpha =frac{pi}{2}$ ,
   $alpha$ Є [-1,1].