Question

$5 x^{2} +4 x-1=0$

Answer 1

$D=b^{2}-4ac=4^{2}-4*5*(-1)=16+20=36$
$sqrt{D}= sqrt{36}=6$
$x_{1}= frac{-4+6}{10}= frac{2}{10}= frac{1}{5}$$[tex]=0,5$
$x_{2}= frac{-4-6}{10}= frac{-10}{10}=-1$
$Otvet;0,5;-1.$