Question

помогите умоляюю ((хоть 4 задания плз

Answer 1

(1)
a)
$0.4sqrt{10}*sqrt{250}+sqrt{169}=0.4*sqrt{2500}+13}=0.4*50+13=boxed{33}$

б)
$sqrt{24}-4sqrt{6}+sqrt{54}=sqrt{6*4}-4sqrt{6}+sqrt{6*9}=sqrt{6}(sqrt{4}-4+sqrt{9})=\=sqrt{6}(2-4+3)=boxed{sqrt{6}}$





(3)
$frac{4-c}{c+2sqrt{c}}=frac{2^2-(sqrt{c})^2}{(sqrt{c})^2+2sqrt{c}}=frac{(2-sqrt{c})(2+sqrt{c})}{sqrt{c}(sqrt{c}+2)}=frac{2-sqrt{c}}{sqrt{c}}=boxed{frac{2}{sqrt{c}}-1}=frac{2sqrt{c}}{c}-1$





(4)
$B=sqrt{0.17^2-0.08^2}=sqrt{(0.17-0.08)(0.17+0.08)}=sqrt{0.9*0.25}=\=0.3*0.5=0.15\A=0.(15)=0.15151515...\A>B$




(5)
$frac{sqrt{15}+4}{4-sqrt{15}}=31+8sqrt{15}\sqrt{15}+4=(31+8sqrt{15})(4-sqrt{15})\sqrt{15}+4=124-31sqrt{15}+32sqrt{15}-8*15\sqrt{15}+4=sqrt{15}+4$
Доказано.

Answer 2

1номер не видно

Answer 3

в смысле?

Answer 4

оо все видно

Answer 5

ты вк есть?