Question

Пожалуйста решите хоть одно

Answer 1

(125)^(1/3) - (625)^(1/4) + 4/(√6 + √2) - (36)^(1/4) + (4)^(1/4) 
 5 - 5 + 4/(√6 + √2) - (√6 - √20 = [(4 - (6 -4)] / (√6 - √2) = 0

2)  [((x^(1/3) * x)^(1/2) *x )^(1/4)] = [(x^(1+1/3))^(1/2) * x]]^(1/4) = [(x^(2/3) * x]^(1/4) =
 x^(5/3) ^(1/4) = x^(5/12)
Если x = 3^(12/5), то [3^(12/5)]^(5/12) = 1