Question

3(arcsinx)^2+2piarcsinx-pi^2=0

Answer 1

$3arcsin^2x+2 pi arcsinx- pi ^2=0\t=arcsinx\3t^2+2 pi t- pi ^2=0\D=(2 pi )^2-4*3*(- pi ^2)=4 pi ^2+12 pi ^2=16 pi ^2=(4 pi )^2\t_1=(-2 pi +4 pi )/6=2 pi /6= pi /3\t_2=(-2 pi -4 pi )/6=-6 pi /6=- pi \\arcsinx= pi /3\x_1= sqrt{3}/2\\arcsinx=- pi \x_2=0$