Question

Решите уравнения:
1)log3(2x-3) = 1;
2)log4(x2+2x-8) = 2.

Answer 1

$log_{3}$(2x-3)=1
2x-3=3
x=3

$log_{4} ( x^{2}+2x-8 )=2$
x^{2}+2x-8=$4^{2}$
x^2+2x-24=0
$x_{1}=-6$
$x_{2}=4$