Question

Решите неравенство:
1) (х-4)(х+3)-5 < х(х+16)
2) х²(6-х)+х³ ≥ 2х(3х+4)-24
3) х³(3-2х)+х²(х+2х²) > 4х(х²-3)+12

Answer 1

1)x^2-x-17 < x^2+16 x
x^2-x-17-x^2-16 x < 0
-17 x-17 < 0
-17 x < 17
x > -1
2)6x^2-x^3+x^3$geq$6x^2+8x-24
6x^2-x^3+x^3-6x^2-8x+24$geq 0$
-8x+24$geq 0$
-8x$geq -24$
x$leq 3$
3)3x^3-2x^4+x^3+2x^4>4x^3-12x+12
3x^3+x^3-4x^3+12x-12>0
12x-12>0
12x>12
x>1

Answer 2

Спасибо огромное)

Answer 3

незачто))))))))