Question

Решите неравенство

y+(x-3)(x+5)< и равно 0

Answer 1

$y+(x-3)(x+5) leq 0, \ y+(x-3)(x+5) = 0, \ y+x^2+2x-15 = 0, \ y=-x^2-2x+15, \ \ a=-1, ysmallfrown; \ x_0=- frac{-2}{2cdot(-1)} = -1, \ y_0=-(-1)^2-2cdot(-1)+15=16; \ (-1;16); \ x=0, y=15, \ y=0, -x^2-2x+15=0, \ x^2+2x-15=0, x_1=-5, x_2=3; \ (0;15), (-5;0), (3;0).$