Question

найти производную ln(sin x/2 )

Answer 1

=(sin x/2)'/sin x/2=$frac{-frac{1}{2}cosfrac{x}{2}}{sinfrac{x}{2}}=-frac{1}{2}сtg frac{x}{2}$

Answer 2

ln(sin x/2 )$(ln(sin frac {x}{2}))'=frac{(sin frac {x}{2})'}{sin frac {x}{2}}=frac {cosfrac {x}{2} *(frac {x}{2})'}{sin frac {x}{2}}=frac {cosfrac {x}{2}}{2sin frac {x}{2}}=frac {tg frac{x}{2}}{2}$