Question

Сократите дробь:
$frac{18^{n+3} }{3^{2n+5}*2^{n-2} }$

Answer 1

$frac{18^{n+3}}{3^{2n+5}*2^{n-2}}=frac{(3^2*2)^{n+3}}{3^{2n+5}*2^{n-2}}=frac{3^{2(n+3)}*2^{n+3}}{3^{2n+5}*2^{n-2}}=\=3^{(2n+6)-(2n+5)}*2^{(n+3)-(n-2)}=3^1*2^1=6$