Question

3x в квадрате - 15 = 0
(x - 3) в квадрате = 100
( х - 4) в квадрате = 6

Answer 1

$3x^2-15=0, \ x^2-5=0, \ (x+sqrt{5})(x-sqrt{5})=0, \ x+sqrt{5}=0, x_1=-sqrt{5}, \ x-sqrt{5}=0, x_1=sqrt{5};$

$(x-3)^2=100, \ (x-3)^2-10^2=0, \ (x-3+10)(x-3-10)=0, \ (x+7)(x-13)=0, \ x+7=0, x_1=-7, \ x-13=0, x_2=13;$

$(x-4)^2=6, \ (x-4)^2-(sqrt{6})^2=0, \ (x-4+sqrt{6})(x-4-sqrt{6})=0, \ x-4+sqrt{6}=0, x_1=4-sqrt{6}, \ x-4-sqrt{6}=0, x_2=4+sqrt{6}.$