Question

Найдите корень уравнения x^2-9=(x-3)^2

Answer 1

x^2-9=(x-3)^2

x^2-9 - (x-3)^2=0

(x-3)(x+3) - (x-3)^2 = 0

(x-3)(x+3-x+3)=0

6(x-3)=0

x-3=0

x=3