Question

Сделайте 1-ое задание

Answer 1

$log_5125=log_55^3=3 \ lg0.01=-2 \ 2^{log_23}=3 \ 3^{2log_37}=49 \ \ log_268-log_217=log_24=2$

Answer 2

$log_ab^c=c*log_ab\log_aa=1\a^{log_ab}=b\log_ab-log_ac=log_afrac{b}{c}\lga=log_{10}a$





(1)
1)
$log_5125=log_55^3=3*log_55=3*1=3$

2)
$lg0.01=lgfrac{1}{100}=lg(10)^{-2}=-2*lg10=-2$

3)
$2^{log_23}=3$

4)
$3^{2log_37}=(3^{log_37})^2=7^2=49$

5)
$log_268-log_217=log_2(frac{68}{17})=log_24=log_22^2=2*log_22=2$