Question

(2tg П/6 - tg П/3):cos П/6

Answer 1

(2tg П/6 - tg П/3)/cos П/6=(2*√3/3 - √3) / √3/2= ((2√3 - 3√3)/3) / √3/2=-√3/3 * 2/√3= 
=-2/3