Question

Помогите решить неравенства:

Answer 1

(3√3)^[x]≥√3
3^[1/2*x+1]≥3^[1/2]
1/2*x+1≥1/2
x+2≥1
x≥-1

(4∛4)^[x]≤∛4
4^[1/3*x+1]≤4^[1/3]
1/3*x+1≤1/3
x+3≤1
x≤-2