Question

пожалуйста,помогите решить

Answer 1

Решение
1)  (y^(1/4) / y^2 = y^(1/4 - 2) = y^(-7/4)
2) [ (3^9)^(1/6)*(2^2*9^2)^(1/6) ] / ((12)^(1/6)) = 3^(12/6) 3^2 = 9
3) [ (108)^(1/6) * 5^(1/3)]  / (100)^(1/6) = (2^(1/3) * 3^(1/2))/ (2^(1/3) = √3