Question

1)x²-4x+3=0
2)x²-6x+5=0

Answer 1

$x^{2} -4x+3=0\D=16-12=4\ sqrt{D} =2\ x_{1} = frac{4+2}{2} =3\ x_{2} = frac{4-2}{2} =1$

$x^{2} -6x+5=0\D=36-20=16\ sqrt{D} =4\ x_{1} = frac{6+4}{2} =5\ x_{2} = frac{6-4}{2} =1$