Question

Помогите решить
sin2x=2sinx-cosx+1

Answer 1

sin 2x = 2 sin x * cos x;
2 sin x * cos x - 2 sin x + cos x - 1 = 0;
2 sin x(cos x - 1) + ( cos x - 1) = 0;
(cos x- 1) *(2 sin x + 1) = ;
cos x - 1 = 0;   
cos x = 1 ; 
 x = 2 pi*k; k - Z.

2 sin x + 1 = 0;
sin x = - 1/2;
x = (-1)^(k+1) * pi/6  + pi*k; k-Z