Question

Naydite znaceniye wrazeniya sin15°cos45°

Answer 1

$sin alpha cdot cos beta =frac{1}{2}(sin( alpha + beta )+sin( alpha - beta ))\\\sin15^0cos45^0=frac{1}{2}(sin60^0+sin(-30^0))=frac{1}{2}(frac{sqrt3}{2}-frac{1}{2})=frac{sqrt3-1}{4}$