Question

упрости..... b(m-7)-7b x(c+1)+c(x-1) y(x-4)+x(3-y) m(k-3)-k(m-5) a(1-b)-a(1+b)
b(2d-5)-b(d+5)               помогите 

Answer 1

b(m-7)-7b  = bm - 7b - 7b = bm - 14b 
x(c+1)+c(x-1)= xc + x + xc - c = 2xc + x - c
y(x-4)+x(3-y) = xy - 4y + 3x - xy = -4y+3x
m(k-3)-k(m-5) = km - 3m - km + 5k = 5k - 3m
 a(1-b)-a(1+b) = a - ab - a - аb = - 2ab
b(2d-5)-b(d+5)= 2bd - 5b - bd - 5b = bd - 10b 

Answer 2

a(1-b)-a(1+b) = a - ab - a - ab = -2ab - that's a correct answer

Answer 3

that's a correct answer

Answer 4

But you didn't have to report it...

Answer 5

I'm sorry

Answer 6

b(m-7)-7b=bm-7b-7b=bm-14b=b(m-14)
x(c+1)+c(x-1)=xc+x+ xc-c = 2xc+x-c =с(2х-1)+х
y(x-4)+x(3-y)=yx-4y+3x-xy=3x-4y
m(k-3)-K(m-5)=mk-3m-km+5k=5k-3m
a(1-b)-a(1+b)=a-ab-a-ab= -2аb -да это правильно
b(2d-5)-b(d+5)=2db-5b-db-5b=db-10b=b(d-10)