Question

Найдите корни уравнения 2х^2 - 13x - 7 = 0

Answer 1

x=(13+-sqrt(169+56))/4=(13+-sqrt(225))/4=(13+-15)/4

x=7

x=-1/2

Answer 2

2х^2 - 13x - 7 =0

d=b^2-4ac=169-4*2*(-7)=225

x1=-1/2

x2=7

Ответ:x1=-0,5 x2=7

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