Question

4log24x-2log2x+1=0 how to do it

Answer 1

Решение
log 2 (4x)^4) - log 2 ((x)^2) + 1 = 0
log 2 ((4x)^4 / ((x)^2)  + log 2 (2) = 0
log 2 (4x^2)*2 = 0
8x^2 = 2^0
x^2 = 1/8
x = 1 / (2√2)