Question

Решить уравнение. 2^8-x^2=4^x

Answer 1

$2^{8-x^2}=4^x \ \ 2^{8-x^2}=2^{2x} \ \ 8-x^2=2x \ \ x^2+2x-8=0 \ \ x_1=-4 \ \ x_2=2$

Answer 2

$2^{8-x^2}=2 ^{2x}$
8-x²=2x
x²+2x-8=0
x1+x2=-2 U x1*x2=-8
x1=-4 U x2=2