Question

10-2^(3*x+1)=16/2^(3*x+1)

Answer 1

$10-2^{3*x+1}=frac{16}{2^{3*x+1}} ;2^{3*x+1}=a\10-a=frac{16}{a}|*a\10a-a^2=16\a^2-10a+16=0\a_1=2 ;a_2=8\2^{3*x+1}=2 2^{3*x+1}=8\3*x+1=1 2^{3*x+1}=2^3\x=0 3*x+1=3\. x=frac{2}{3}$