Question

7*4^x-9*14^x+2*49^x=0

Answer 1

$7*4^x-9*14^x+2*49^x=0\7*2^{2x}-9*2^x*7^x+2*7^{2x}=0|:7^{2x}\7*(frac{2}{7}})^{2x}-9*(frac{2}{7}})^{x}+2=0\frac{2}{7}^x_{1,2}=frac{9^+_-5}{14}\frac{2}{7}^x=1 ;frac{2}{7}^x=frac{2}{7}\x=0 x=1$