Question

Вычислить: y`(0)=sin^2 ln e^x .

Answer 1

$y=sin^2ln(e^{x})=(sin(lne^{x}))^2=(sin(xlne))^2=(sinx)^2\\lne=1\\y'=2sinxcdot cosx=sin2x\\y'(0)=sin(2cdot 0)=sin0=0$