Question

(√х )-4/√(2+х) +√(2+х)=0

Answer 1

$sqrt{x} - frac{4}{ sqrt{2+x} }+ sqrt{2+x} =0$

ОДЗН: $x geq 0$

$sqrt{x} - frac{4}{ sqrt{2+x} }+ sqrt{2+x} =0|*sqrt{2+x}$ 
$sqrt{x(2+x)} -4+ (sqrt{2+x}) ^{2} =0$
$sqrt{ x^{2} +2x} -4+2+x=0$
$sqrt{ x^{2} +2x}=2-x$
$( sqrt{ x^{2} +2x})^{2} = (2-x)^{2}$
$x^{2} +2x=4-4x+ x^{2}$
$6x=4$
$x= frac{2}{3}$
Ответ: $x= frac{2}{3}$