Предмет: Алгебра, автор: terekhovtony

Постройте график функции y = sinx – 1.
а) Укажите область значений данной функции;
б) Найдите наибольшее и наименьшее значения функции на интервале (π/3; 3π/2).

Ответы

Автор ответа: massg
0
а) область значения sinx  -1; 1   область значения sinx-1
-1-1 ; 1-1 ? т.е. получается от -2 до 0

б) наибольшее 0 при х=п/2, наименьшее при 3п/2  = -2
Приложения:
Автор ответа: terekhovtony
0
В задании б) не п/2,а п/3
Автор ответа: massg
0
п/3 начало интервала, при п/2 наибольшее значение функции на этом интервале, оно то и есть при х=п/2
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