Question

2 в степени log 16 (6 x + 7) = 7

Answer 1

$2^{log_{16}(6x+7)}=7\\log_{16}(6x+7)=log_27\\log_{2^4}(6x+7)=log_27\\ frac{1}{4}log_2(6x+7)=log_27\\log_2 sqrt[4]{6x+7}=log_27\\ sqrt[4]{6x+7}=7\\ left { {{6x+7>0} atop {6x+7=7^4}} right. \\ left { {{6x>-7} atop {6x+7=2401}} right.\\ left { {{x>-7/6} atop {6x=2394}} right.\\ left { {{x>-7/6} atop {x=399}} right.\\x=399$