Предмет: Геометрия, автор: evgenya13a

В ромбе ABCD угол BAD равен 46 градусов, О-точка пересечения диагоналей. Найдите углы треугольника AOB. Ответ: угол ABO = ? , угол OAB = ?, угол BOA__ ?

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Автор ответа: BSergey9914

0

1) Т. к. углы ромба всегда пересекаются под прямым углом, то угол BOA = 90 градусов, а значит, треугольник AOB - прямоугольный
2) Т. к. диагонали ромба являются биссектрисами его углов, то угол OAB = $frac{1}{2}$ угла BAD = $frac{46}{2}$ = 23 градуса
3) Угол ABO = 90 градусов - угол OAB = 90 - 23 = 67 градусов

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