Question

Lg x-2 lg3=lg 7- lg 9 (16-x)

Answer 1

$lgx-2lg3=lg7-lg9(16-x)\lgfrac{x}{9}=lgfrac{7}{9(16-x)}\x=frac{7}{16-x}\x^2-16x+7=0\x_{1,2}=8^+_-sqrt{57}$