Question

срочно!!! решите уравнение: x^5+x^4-x^3-x^2-6x-6=0 

Answer 1

$x^{5} + x^{4} - x^{3} - x^{2} -6x-6=0 \ x^{4} (x+1)- x^{2} (x+1)-6(x+1)=0 \ ( x^{4} - x^{2} -6)(x+1)=0 \ x^{4} - x^{2} -6=0 \ x^{2} =t \ t ^{2} -t-6=0 \ D=25 \ sqrt{D} =5 \ t _{1} = frac{1+5}{2} = frac{6}{2} =3 \ t _{1} = frac{1-5}{2} = frac{-4}{2} =-2 \ x^{2} neq -2 \ \ x^{2} =3\x=+- sqrt{3}$

$\ x+1=0\x=-1$