Question

Решите сроооочно
log0,7(7x-10)<2log0,7x

Answer 1

$log_{0,7}(7x-10)<2log_{0,7}x\\ left { {{7x-10>0}atop {x>0}}right.\\left{ {{x>10/7}atop {x>0}} right.\\x>10/7\x>1frac{3}{7}\\log_{0,7}(7x-10)<log_{0,7}x^2\7x-10>x^2\x^2-7x+10<0\(x-5)(x-2)<0$

          +                           -                          +
_____________2____________5_____________

x∈(2;5)