Предмет: Геометрия, автор: suhov100krut

Сторона AB треугольника АВС равны 17 см,сторона АС вдвое больше стороны АВ, а сторона ВС на 10 см меньше стороны АС.Найти периметр треугольника АВС

Ответы

Автор ответа: Patronuss

0

АС = 17*2 = 34
BC = 34 - 10 = 24
P = 34 + 24 + 17 = 75

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