Question

Решите, пожалуйста:(m - 4n)^2 : (32n^2 - 2m^2)

Answer 1

$frac{(m-4n)^2}{32n^2-2m^2}=\\frac{(4n-m)^2}{2(16n^2-m^2}=\\frac{(4n-m)^2}{2((4n)^2-m^2}=\\frac{(4n-m)^2}{2(4n-m)(4n+m)}=\\frac{4n-m}{2(4n+m)}=\\frac{4n-m}{8n+2m}$