Предмет: Химия, автор: darkeid

Определите объём водорода который вступает в реакцию с 14 г азота.
H2+N2->NH3

Ответы

Автор ответа: lyubavasil
0
V-?    14г
3H2  +N2->2NH3
67,2л  28г
V(H2)=67,2*14/28=33,6(л)
Ответ:33,6л
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