Question

преобразуйте в дробь выражения:
а) x+2/x+3 - x-1/x

б)2y- 4y²/2y-1 -1

в)5a²/5ab-b² - b/25a-5b

г)x²/x³-x + 1/2-2x

Answer 1

$frac{x+2}{x+3}- frac{x-1}{x}= frac{x^2+2x-(x-1)(x+3)}{x(x+3)}=frac{x^2+2x-x^2-2x+3}{x(x+3)}=frac{3}{x(x+3)}$
$2y- frac{4y^2}{2y-1}-1= frac{2y(2y-1)-4y^2-1(2y-1)}{2y-1}= frac{4y^2-2y-4y^2-2y+1}{2y-1}= frac{1-4y}{2y-1}$
$frac{5a^2}{5ab-b^2}- frac{b}{25a-5b}=frac{5a^2}{b(5a-b)}- frac{b}{5(5a-b)}= frac{25a^2-b^2}{5b(5a-b)}= frac{(5a-b)(5a+b)}{5b(5a-b)}= frac{5a+b}{5b}$
$frac{x^2}{x^3-x}+ frac{1}{2-2x}=frac{x^2}{x(x^2-1)}+ frac{1}{2(1-x)}=frac{x^2}{x(x-1)(x+1)}- frac{1}{2(x+1)}= frac{2x^2-1*x(x-1)}{2x(x-1)(x+1)} \ =frac{2x^2-x^2+x}{2x(x-1)(x+1)}=frac{x^2+x}{2x(x-1)(x+1)}=frac{x(x+1)}{2x(x-1)(x+1)}= frac{1}{2(x-1)}$

Answer 2

Спасибо

Answer 3

пожалуйста